10-7-14 Current and Resistance

This is a simple application which is done by people with doctorates in Electrical Engineering from Harvard cannot do. One wire, one battery, and one light bulb. recognizing how to complete the circuit by attaching signal and ground

This box detects electric fields.

This picture reflects in laymen terms, what current is. It shows a closed loop and the position of electrons in the battery and the movement of energy and charge throughout the wires.

This is all that is required to make the light bulb shine bright like a diamond. A diamond with a light on it of course. 

This is the derivation of power. P=IV. The voltage that is carried in a current equates to the amount of joules per second, or the power of the process.

This picture is disturbing. The excercise is to show that the current is the same throughout. I have no idea how these inequalities could work out. This dumbfounded and in all honesty hurts my brain to look at.

These are a collection of ammeters. The are implemented into a circuit and measure the current. Current is measured in Amperes, which is a measurement Coulombs per second, or the change in charge over the change in time. Another equation for currant is that I=pqva. where v is the drift velocity, measured in meters/second. p is the number density, or the number of charges per unit volume (#/m^3). q is the magnitude of the charge, for example the magnitude of the charge on an electron is 1.602x10^-19. and finally a is cross sectional area perpendicular to the flow, measured in m^2. this is often known as a gauge for the wire.

This circuit uses an ammeter to measure the current, as well as a switch to open and close the circuit. It shows that without a complete loop there is no current and no voltage gets to any of the hardware.

This board is looked at a wire. it is measure charge relative to the volume of the wire and the number of charge carriers in the wire. It uses the conversion for current and implements it into the charge  and then calculates the drift velocity.

This graph shows the relationship between current and voltage. This relationship can be put in the form y=slope x as well it crosses through the origin, which is good.

In this exercise the slope of the line reflects well in OHM's law. The V=IR. This means that the slope of the line is the resistance, this is the resistance in the wire. 

• When a potential difference V is applied across the ends of a wire a steady current I quickly begins to flow. In different materials the amount of current that flows will be different even if the voltage is the same.
• The scattering of charge carriers off impurities, imperfections, and vibrations of the atomic lattice creates the resistance to the flow of charges in the wire.

These are three different positions and measuring the resistance in the wires. All of them behave ohmicly and show the relationship V=IR.

This is Georg Simon Ohm, he discovered Ohm's Law. He is an all around badass.

This is Ohm's Law. 

9_30_14 Gauss' law

HEY PROFESSOR MASON

9_25_2014 Electric Flux

This equation shows the similarity between charge and projectile motion.

This is a problem looking at the torque on two particles in a field. 

This display is showing the field between to charges.

This is the basic formula for flux.

These are the conceptual rules that apply to flux.

9_23_2014 Gauss Law

These are general standards that are found when looking at E fields.

These problems pertain to a particle in between to bars in a charged field. They are problems one concepts from activphysics, provided by pearson.

There are two particles equidistant from a particle, which is a small number above the line between them. Both have opposing charges, so one pushes it up while one pulls it down, therefor it has no direction in the j-hat direction. Because they opposite charges, but they both posses the same magnitude of charge, the force is just doubled in the direction of the negative charge.

This is a simple problem in which multiple points are looked at for the field effect of the charges in those locations.

The above problem was solved using a formula in which you can choose any point and then adjust its relative location to a charge and then sum the values to calculate the Field at that location.

This bar has a uniform charge through out, what is the effect of the field cause by the bar on the point .05 meters above the center of the bar? What's wrong? you don't know? Don't worry, I have the data tabulated on the next slide so you can see the parts and the formula is printed on the board above.

This is used as though the charge is at one end of the bar, instead of directly over the bar. and then it is recalculated with at the point 0.05 m above the middle of the poll.

This is the effects of the field using smaller dx. and then after words (after A21) looking at the effect on random points to find the magnitude of the E along 1 dimensions.

I am the master of this game, there is no one better than me.

After completing this, I was emailed by IEEE about a research position. They would research me and try to recreate me.

9_18_2014 Electric Field

These are some animal skins that Mr. Mason got when bartering on the Oregon Trail.

Calm down. This is not magic. It is a an electrical field holding that balloon to the glass. I will explain.

This is silk. It hates animal fur. They produce different electrical fields when rubbed against a balloon.

This is a quantitative formula for calculating electrical fields. That is a free body diagram. #Physics.

This is a layman's definition of charge. Included is a very similar definition of mass. #Chemistry.

This is the free body diagram regarding the balloon on the window.

This is the sum of forces looking at the charge that is pushing or pulling something with a like charge. In this case it is a hanging charge being pushed by another charge.

This is the tracking of two magnets moving closer together and the calculation of the force constant or the electrical field caused by the proximity of the charges.

This is a physical simulation and conversion from the chart.Conclusion:Yes, we were able to tell immediately that it was an inverse relationship. Then by looking at the slope we figured it must be and inverse square due to the steepness of the graph. They are the same value, so the percent difference is 0. However our equation for the function does not accurately describe the function too 100%. A=kq^2 => q = sqrt(A/k)= 5.25 * 10^-8A=k(q/2)(q)=k(q^2/2) => q = sqrt(2A/k)= 7.43 * 10^-8 and q/2 = 3.72*10^-8No, we derived the force in the x direction from using a fbd and equations for static equillibrium. Since this is what we used for our force equation our force will only be positive since distance is positive (measure from origin). Hence the best we can do is find the absolute value of q.Uncertainty for force can be found, systematic error can be found for not accounting for the mass of the string string and small things like friction and minute spinning of the string. We also assume that acceleration is equal to zero.

This is a van de graaff generator. It gathers electrostatic and causes the outside to share the same charge as things that touch it.

this is the mechanism that creates the static charge. The copper wires are pulling electrons off the rubber, but at the bottom the rubber is regaining electrons from the base.

9_16_2014 Thermo electric cooler

This is an example of a engine in which the heat from the boiling water powers the propeller.
It does a large amount of work as you can see how excited DJ is. This is a Stirling engine.

This is an equation for cooling given a power and the change in temperature. COPc is the Tc over Th-Tc. COPh is the Th over Th - Tc. To calculate Qc we set it equal to W multiplied by COPc by the power.

given that 5 meters is a floor and out object weighs 100kg, how long would it take to climb multiple floors if it takes 760 watts. converting watts to joules per minute.how many floors could you cover in a minute, 9.3. how much long do you have energy for?

you have energy for 13.7 minutes. calculating the change in temperature and calculating a COPreal. a Qh W and Qc are all calculated.

In the problem entropy is equal to zero.The work from one revolution is equal to Qa-Qb. The entropy of the system is equal to the entropy of heat plus the entropy of work plus the entropy of cold. there is no entropy from work and the entropy from heat and from cold is just mcln(Tf/T(h o c)) relatively so the final equation is mcln(tf^2/TaTb) which is equal to zero, as m and c are both constants tf^2/TaTb must equal one.so then Tf=sqrtTaTb.