9_25_2014 Electric Flux

This equation shows the similarity between charge and projectile motion.

This is a problem looking at the torque on two particles in a field. 

This display is showing the field between to charges.

This is the basic formula for flux.

These are the conceptual rules that apply to flux.

9_23_2014 Gauss Law

These are general standards that are found when looking at E fields.

These problems pertain to a particle in between to bars in a charged field. They are problems one concepts from activphysics, provided by pearson.

There are two particles equidistant from a particle, which is a small number above the line between them. Both have opposing charges, so one pushes it up while one pulls it down, therefor it has no direction in the j-hat direction. Because they opposite charges, but they both posses the same magnitude of charge, the force is just doubled in the direction of the negative charge.

This is a simple problem in which multiple points are looked at for the field effect of the charges in those locations.

The above problem was solved using a formula in which you can choose any point and then adjust its relative location to a charge and then sum the values to calculate the Field at that location.

This bar has a uniform charge through out, what is the effect of the field cause by the bar on the point .05 meters above the center of the bar? What's wrong? you don't know? Don't worry, I have the data tabulated on the next slide so you can see the parts and the formula is printed on the board above.

This is used as though the charge is at one end of the bar, instead of directly over the bar. and then it is recalculated with at the point 0.05 m above the middle of the poll.

This is the effects of the field using smaller dx. and then after words (after A21) looking at the effect on random points to find the magnitude of the E along 1 dimensions.

I am the master of this game, there is no one better than me.

After completing this, I was emailed by IEEE about a research position. They would research me and try to recreate me.

9_18_2014 Electric Field

These are some animal skins that Mr. Mason got when bartering on the Oregon Trail.

Calm down. This is not magic. It is a an electrical field holding that balloon to the glass. I will explain.

This is silk. It hates animal fur. They produce different electrical fields when rubbed against a balloon.

This is a quantitative formula for calculating electrical fields. That is a free body diagram. #Physics.

This is a layman's definition of charge. Included is a very similar definition of mass. #Chemistry.

This is the free body diagram regarding the balloon on the window.

This is the sum of forces looking at the charge that is pushing or pulling something with a like charge. In this case it is a hanging charge being pushed by another charge.

This is the tracking of two magnets moving closer together and the calculation of the force constant or the electrical field caused by the proximity of the charges.

This is a physical simulation and conversion from the chart.Conclusion:Yes, we were able to tell immediately that it was an inverse relationship. Then by looking at the slope we figured it must be and inverse square due to the steepness of the graph. They are the same value, so the percent difference is 0. However our equation for the function does not accurately describe the function too 100%. A=kq^2 => q = sqrt(A/k)= 5.25 * 10^-8A=k(q/2)(q)=k(q^2/2) => q = sqrt(2A/k)= 7.43 * 10^-8 and q/2 = 3.72*10^-8No, we derived the force in the x direction from using a fbd and equations for static equillibrium. Since this is what we used for our force equation our force will only be positive since distance is positive (measure from origin). Hence the best we can do is find the absolute value of q.Uncertainty for force can be found, systematic error can be found for not accounting for the mass of the string string and small things like friction and minute spinning of the string. We also assume that acceleration is equal to zero.

This is a van de graaff generator. It gathers electrostatic and causes the outside to share the same charge as things that touch it.

this is the mechanism that creates the static charge. The copper wires are pulling electrons off the rubber, but at the bottom the rubber is regaining electrons from the base.

9_16_2014 Thermo electric cooler

This is an example of a engine in which the heat from the boiling water powers the propeller.
It does a large amount of work as you can see how excited DJ is. This is a Stirling engine.

This is an equation for cooling given a power and the change in temperature. COPc is the Tc over Th-Tc. COPh is the Th over Th - Tc. To calculate Qc we set it equal to W multiplied by COPc by the power.

given that 5 meters is a floor and out object weighs 100kg, how long would it take to climb multiple floors if it takes 760 watts. converting watts to joules per minute.how many floors could you cover in a minute, 9.3. how much long do you have energy for?

you have energy for 13.7 minutes. calculating the change in temperature and calculating a COPreal. a Qh W and Qc are all calculated.

In the problem entropy is equal to zero.The work from one revolution is equal to Qa-Qb. The entropy of the system is equal to the entropy of heat plus the entropy of work plus the entropy of cold. there is no entropy from work and the entropy from heat and from cold is just mcln(Tf/T(h o c)) relatively so the final equation is mcln(tf^2/TaTb) which is equal to zero, as m and c are both constants tf^2/TaTb must equal one.so then Tf=sqrtTaTb.

9/11/2014

Physics is Awesome and Physics is Weird

The first law of thermodynamics

by Mike Eats

When a candle is placed into a graduated cylinder, it becomes extinguished. When a candle is placed into a graduated cylinder and then another cylinder is placed inside, it creates a cycle. In this cycle the CO2 produced by the reaction from the flame and burning wax rises due to the heat and outside of the cylinder oxygen is pulled through by the raised temperature, causing a cycle which will keep the candle lit.

a Candle that is lit, inside of a large jar is then dropped, what will happen to the flame?
My group said it would burn more brightly.
We were wrong.
Because the static heat of the flame is lost when the candle is in free fall, The flame can no longer rely on convection for heat to speed up the chemical reaction. It must rely on diffusion which is not as fast a reaction for burning.

The spring is an example of a negative work reaction. Alone the spring does no work and just sits in equilibrium, only when work is applied to the spring to contract it is the spring able to do work.
Similar to a spring is a cylinder of gas at standard temperature and pressure. If work is applied to it, like a spring it can do work in return; likewise, if it is heated it can also produce work. 

This a review of the relationships between pressure, volume and temperature.
This shows the direct relationship between volume and temperature and between temperature and pressure.
This also shows the inverse relationship between pressure and volume.

These equations reflect the previous graphs. These two equations reflect the relationship between volume and temperature (#4) and also pressure and temperature (#5).  Using the ideal gas law and treating all the other portions of the equation as constant, this is an introduction to processes in which either the volume, temperature, or pressure is constant.

This final equation is using the relationship between pressure and volume when temperature is constant. This is a difficult situation as both pressure and volume must change without temperature changing, which though may be negligible is not necessarily constant.

This equation is calculating  work in a system without knowing temperature. In this case it is a water tower and it is lifting water using a change in pressure due to the heat. In this cause the equation for work is delta U. Because temperature is unknown the equation for work is P1V1 multiplied by the natural log of V2/V1. Much physics very wow.

This is the total work, it includes the work done by the the gas and work done by the fluid and finally work done by the mass of the water lifted.
The work done by the mass of the water is equal to mgh
the work done by the gas is PairVtln4
The work done by the air is 1/4PairVt
as the work  done by the mass is positive and the work done by the gas is in the same direction, it is the sum of those two subtracted by the work done by air.
air is the fourth derivative of displacement.

These are the graphs of pressure vs volume, and they identify the four processes that make up a heat engine. When temperature is constant and delta U is zero; it is an isothermal process. When pressure is constant the graph is a horizontal line and it is called isobaric. When volume is constant and W=0 the graph is a vertical line is called isobaric. The final equation is when Q is 0 and that is called adiabatic, the word is similar to Diablo, which is Spanish for the devil.

An example of a heat engine. It is important to recognize that in this engine it is only made up of isobaric and isochloric processes. Next the W and the Q and the delta U is all calculated for each step as well the energy for each step is looked at in each step. In this case energy is 3/2PV.

This board is the culmination of all the findings as well as the equation for efficiency.

This is the equation for efficiency, Conceptually it is the amount of work you get done by the amount of heat you put into the system. that being said the perfect engine would be rated at 1. This is the rating on the engine of the 2006 Chevy Colorado.

This is the practical application for a common efficiency of a heat engine.

This gas law apparatus is creating an environment with constant temperature. Because constant temperature is difficult to achieve, the experiment is not done tracking the pressure and volume over time, but at instantaneous moments.

This is using the previous device to calculate work. Because work is equal to the integral of P with reference to Volume, then pressure must be defined with regards to volume. This becomes the integral of nRT over V. nRT is all constant so it just becomes the natural log of the final volume divided by the initial volume.

#physics.
This is an example of a cycle and the idea of using heat to contract rubber and then allowing it to cool to expand.

Gas Law and Kinetic Theory

by Michael Pryor

This is a representation of the conservation of energy. This is a very poor example, because the light bulb cannot charge the battery. A better example would be to view the Q as something that either produces or gives off heat specifically and then something that either takes work or does work itself. Although the light bulb does give off heat, it is not a good example of its change in energy. An oven is a good example of a change in temperature, but a poor example of doing work, because the work does is not visually apparent. 

In the perspective of the gas laws, work is equal to pressure of a change in volume.
Given that pressure is constant, then the change in volume can be displayed as the change in volume due to the coefficient of heat expansion. The initial volume is the mass divided by the density.
The mass is calculated using the specific heat and the change in temperature.
This shows that because of the density of this object the heat that the object absorbs is much greater than the work that the object does in its expansion due to its change in energy.

Force is equal to the change in pressure over an area. This means pressure is also equal to a force over an area.
If the mass is constant then force is equal to the mass multiplied by the change in velocity, or the velocity squared divided by its displacement.
 Given that the area is a square, its formula is is x squared.
The new formula becomes the sum of the mass multiplied by velocity in one direction squared all divided by the displacement (x) cubed.
The numerator is very similar to the formula for kinetic energy. If that adjustment is made to include the kinetic energy of a an atom in a gaseous state, then the numerator must be multiplied by two and the number of atoms must be accounted for, The atom moves in three dimensions, this means that there is an adjustment of 3. This is proved when you calculate the magnitude of the cube and you make all three dimensions equal, as in a cube.

 Given the initial equation that PV=2/3N*E=N*Kb*T where Kb is the Boltzman constant.
Kinetic energy can be equated to 3/2*Kb*T and that can be equated to 1/2*m*(v)squared
Velocity is then equal to the square root of (3*Kb*T)/m
If Q is equal to W then there is no change in the energy of the system.
Which means the equation is in equilibrium and any fluctuation are met with equal values on either side of the equation.
Given a constant pressure and a constant number of molecules. The question can be redced to 3/2*The change in temperature/actual temperature=the opposite of the change in volume/actual volume
When both sides are integrated, the temperature to the -3/2 power is equal to the volume.

These calculations better represent the calculation of force from a change in pressure over a change in temperature, From the earlier equation in which force equals the change in mass multiplied by velocity plus the change in velocity multiplied by mass.

In this experiment the change in volume equates to a change in temperature. As the volume decreases then temperature must increase, because there is no significant change being done to the energy in the system.
Theoretically the final temperature inside the syringe is 604 K this is a significant jump from its original temperature of
293 K and is enough to light a small piece of cotton on fire inside of the syringe.

Physics like a Boss.