9_23_2014 Gauss Law

These are general standards that are found when looking at E fields.

These problems pertain to a particle in between to bars in a charged field. They are problems one concepts from activphysics, provided by pearson.

There are two particles equidistant from a particle, which is a small number above the line between them. Both have opposing charges, so one pushes it up while one pulls it down, therefor it has no direction in the j-hat direction. Because they opposite charges, but they both posses the same magnitude of charge, the force is just doubled in the direction of the negative charge.

This is a simple problem in which multiple points are looked at for the field effect of the charges in those locations.

The above problem was solved using a formula in which you can choose any point and then adjust its relative location to a charge and then sum the values to calculate the Field at that location.

This bar has a uniform charge through out, what is the effect of the field cause by the bar on the point .05 meters above the center of the bar? What's wrong? you don't know? Don't worry, I have the data tabulated on the next slide so you can see the parts and the formula is printed on the board above.

This is used as though the charge is at one end of the bar, instead of directly over the bar. and then it is recalculated with at the point 0.05 m above the middle of the poll.

This is the effects of the field using smaller dx. and then after words (after A21) looking at the effect on random points to find the magnitude of the E along 1 dimensions.

I am the master of this game, there is no one better than me.

After completing this, I was emailed by IEEE about a research position. They would research me and try to recreate me.