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| This is Carl Friedrich Gauss. Badass. |
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| This is the application of gauss's law and other formula's. It was left on the board after someone else's class. Gotcha. |
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| This the equations for circuits. resistance vs capacitance. series vs parallel. |
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The
center bulb will remain OFF. Because the two sides of the circuit connected by
the middle wire are at the same potential, no current can flow in that wire,
and the bulb will not be lit.
The fundamental feature for this circuit is that
the potentials at the points on opposite sides of the switch are the same
before the switch is closed. This can be seen by noting that the two batteries
are identical and the two light bulbs are identical. Therefore, closing the
switch does not do anything to the circuit. |
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Two
important points are relevant to the explanation of this result. First, note
that the potential at the point where the third battery joins the circuit of
the other two remains the same when the switch is closed. This is so because
all of the batteries are the identical, and the potential along the light bulb
wire is divided equally between the bulbs because they are identical.
Therefore, closing the switch does not do anything to the circuit.
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